Berapa bilangan oksidasi fe, s dan o dalam senyawa fe², (so⁴) 3?
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Jawaban:
Fe = +15
S = -2
O = -2
Penjelasan:
Fe2(SO4)3 = 0
Fe2S3O12 = 0
Fe2 + 3×S + 12×O = 0
Fe2 + 3×(-2) + 12×(-2) = 0
Fe2 - 6 - 24 = 0
Fe2 = +30
Fe = +15
S3 = -6
S = -2
O12 = -24
O = -2
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